What will be the output of the following PHP code?$author = "nachiketh@example.com";$author = str_replace("a","@",$author);echo "Contact the author of this article at $author."; Options: A . &nbspError B . &nbspContact the author of this article at n@chiketh@ex@mple.com C . &nbspContact the author of this article at nachiketh@ex@mple.com D . &nbspCont@ct the @uthor of this @rticle @t n@chiketh@ex@mple.com

What will be the output of the following PHP code?$author = "nachiketh@example.c

Question

What will be the output of the following PHP code?$author = "nachiketh@example.com";$author = str_replace("a","@",$author);echo "Contact the author of this article at $author.";

Options:

A . Error

B . Contact the author of this article at n@chiketh@ex@mple.com

C . Contact the author of this article at nachiketh@ex@mple.com

D . Cont@ct the @uthor of this @rticle @t n@chiketh@ex@mple.com

Answer: Option B

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