Question
What was the day of the week on 15th August 1947?
Answer: Option B
Answer: (b)
Odd days in 1600 yrs = 0
Odd days in 300 yrs = 1
46 yrs = (11 leap year + 35 ordinary year)
= (11x2 + 35 x 1) = 1 odd day
∴ Odd days in 1946 yrs = (0+ 1+ 1) = 2
Month
Odd days
January
3
February
0
(ordinary year)
March
3
April
2
May
3
June
2
July
3
August
1 i.e, (15 ÷ 7)
Total 17 17 ÷ 7= remainder 3 odd days
Total odd days =2 + 3 = 5
∴ Required day = Friday
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Answer: (b)
Odd days in 1600 yrs = 0
Odd days in 300 yrs = 1
46 yrs = (11 leap year + 35 ordinary year)
= (11x2 + 35 x 1) = 1 odd day
∴ Odd days in 1946 yrs = (0+ 1+ 1) = 2
Month
Odd days
January
3
February
0
(ordinary year)
March
3
April
2
May
3
June
2
July
3
August
1 i.e, (15 ÷ 7)
Total 17 17 ÷ 7= remainder 3 odd days
Total odd days =2 + 3 = 5
∴ Required day = Friday
Was this answer helpful ?
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