Answer: Option B
Answer: (b)
28th August 2009 means,
2008 complete years + First 7 months of the year 2009 + 28 days of August
Number of odd days in 2000 yrs = 0
Number of odd days from 2001 yrs to 2008 yrs
 
Year
Number of odd days
2001
1
2002
1
2003
1
2004
2
2005
1
2006
1
2007
1
2008
2
 
2001 2002 2003 2004 2005 2006 2007 2008  1 1 1 2 1 1 1 2
=1+1+1+ 2+ 1+1+1+2 = 10
= 7 x1+ 3 = 3 odd days
Number of odd days in 2009,
Month
Odd days
January
3
February
0
(ordinary year) 
March
3
April
2
May
3
June
2
July
3
August
0
January February March April May July  August 3 0 3 2 3 2 3 0
= 3 + 0 + 3 + 2 + 3 + 2 + 3 + 0
= 16 = 7 x 2 + 2 = 2 odd days
Total number of odd days till 28th August 2009
= 0 + 3 + 2 = 5
So, the required day is Friday.