Question
What was the day of the week on 28th May 2006?
Answer: Option C
Answer: (c)
Odd days in 1600 yrs = 0
Odd days in 400 yrs = 0 5 yrs = (4 ordinary year + 1 leap year)
= (4 x 1+ 1 x 2) = 6 odd days
Month
Odd days
January
3
February
0
(ordinary year)
March
3
April
2
May
0 i.e,(28 ÷ 7)
Total
8
Total odd days = 8 + 6 = 14 = 0 odd day
∴ Required day Sunday
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Answer: (c)
Odd days in 1600 yrs = 0
Odd days in 400 yrs = 0 5 yrs = (4 ordinary year + 1 leap year)
= (4 x 1+ 1 x 2) = 6 odd days
Month
Odd days
January
3
February
0
(ordinary year)
March
3
April
2
May
0 i.e,(28 ÷ 7)
Total
8
Total odd days = 8 + 6 = 14 = 0 odd day
∴ Required day Sunday
Was this answer helpful ?
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