Answer: Option A
Answer: (a)
15th August 1949 means,
1948 complete year + First 7 months of the year 1949 + 15 days of August
Number of odd days in 1600 yrs = 0
Number of odd days in 300 yrs = 1
Number of odd days in 48 yr (36 non - leap years + 12 leap years)
= 36 × 1 + 12 × 2
= 60 = 7 × 8 + 4 = 4
odd days From 1st January 1949 to 15th August 1949
Number of odd days in 1949,
January
3
February
0
March
3
April
2
May
3
June
2
July
3
August
(15 ÷ 7) = 1
Total number of odd days in 1949 = 3 + 0 + 3 + 2 + 3 + 2 + 3 + 1 = 17
= 7 × 2 + 3 = 3 odd day
Total odd days = 1 + 4 + 3 = 8
= 1 odd days
Since, 1 is the code for Monday.
Therefore, the required day was Monday.