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Walking $6/7$th of his usual speed, a man is 12 minutes late. The usual time taken by him to cover that distance is
Options:
A .  1 hour 20 minutes
B .  1 hour 15 minutes
C .  1 hour 12 minutes
D .  1 hour
Answer: Option C
Answer: (c)Time and speed are inversely proportional.Usual time × $7/6$ - usual time= 12 minutesUsual time × $1/6$ = 12 minutesUsual time = 72 minutes= 1 hour 12 minutesUsing Rule 8,Here, A = 6, B = 7, t = $12/60 = 1/5$ hrs.Usual time= $\text"A"/\text"Diff of A and B"$ × time= $6/{(7 - 6)} × 1/5 = 1{1}/5$ hrs.= 1 hrs. 12 minutes

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