Question
Two men start together to walk a certain distance, one at 4 km/h and another at 3 km/h. The former arrives half an hour before the latter. Find the distance.
Answer: Option C
Answer: (c)If the required distance be x km, then$x/3 - x/4 = 1/2$${4x - 3x}/12 = 1/2$$x/12 = 1/2$ ⇒ x = 6 kmUsing Rule 9,Here $S_1 = 4, t_1 = x, S_2 = 3, t_2 = x + 1/2$$S_1t_1 = S_2t_2$$4 × x = 3(x + 1/2)$$4x - 3x = 3/2 x = 3/2$Distance= $4 × 3/2$ = 6 kms
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Answer: (c)If the required distance be x km, then$x/3 - x/4 = 1/2$${4x - 3x}/12 = 1/2$$x/12 = 1/2$ ⇒ x = 6 kmUsing Rule 9,Here $S_1 = 4, t_1 = x, S_2 = 3, t_2 = x + 1/2$$S_1t_1 = S_2t_2$$4 × x = 3(x + 1/2)$$4x - 3x = 3/2 x = 3/2$Distance= $4 × 3/2$ = 6 kms
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