Question
Two factories are sounding their sirens at 800 Hz. A man goes from one factory to the other at a speed of 2 m/s. The velocity of sound is 320 m/s. The number of beats heard by the person in 1 s will be
Answer: Option D
:
D
When the man is approaching the factory,
n′=(v+v0v)n=(320+2320)800=(322320)800
When the man is going away from the factory,
n"=(v−v0v)n=(320−2320)800=(318320)800∴n′−n"=(320−318320)800=10Hz
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:
D
When the man is approaching the factory,
n′=(v+v0v)n=(320+2320)800=(322320)800
When the man is going away from the factory,
n"=(v−v0v)n=(320−2320)800=(318320)800∴n′−n"=(320−318320)800=10Hz
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