A man standing on a platform hears the sound of frequency 605 Hz coming from 550

Question

A man standing on a platform hears the sound of frequency 605 Hz coming from 550 Hz train whistle moving towards the platform. If the velocity of sound is 330 m/s. What is the speed of train?

Options:

A . 30 m/s

B . 35 m/s

C . 40 m/s

D . 45 m/s

Answer: Option A
:
A
Apparent Frequency is given by:

n^{'} = n (\frac{v + v_{0}}{v - v_{s}})

605 = 550 (\frac{330 + 0}{330 - v_{s}})

v_{s} = 30 m / s

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