Question
Two blocks of mass 4 kg and 6 kg are placed in contact with each other on a frictionless horizontal surface. If we apply a push of 5 N on the heavier mass, the force on the lighter mass will be
Answer: Option C
:
C
Letm1=6kg,m2=4kgandF=5N(given) Force on the lighter mass =m2×Fm1+m2=4×56+4=2N
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:
C
Letm1=6kg,m2=4kgandF=5N(given) Force on the lighter mass =m2×Fm1+m2=4×56+4=2N
Was this answer helpful ?
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