Question
Two adjacent sides of a rectangle are 5x2−3y2 and x2−2xy. Find its perimeter. [3 MARKS]
Answer:
:
Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Given that:
Two adjacent sides of arectangleare 5x2−3y2and x2−2xy.
The perimeter of a rectangle is given by:
Perimeter of a rectangle = 2 (Length +Breadth)
=2[(5x2−3y2)+(x2−2xy)]
=[10x2−6y2)+(2x2−4xy)]
=12x2−6y2−4xy
So, the perimeter of the rectangle is12x2−6y2−4xy.
Was this answer helpful ?
:
Formula: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Given that:
Two adjacent sides of arectangleare 5x2−3y2and x2−2xy.
The perimeter of a rectangle is given by:
Perimeter of a rectangle = 2 (Length +Breadth)
=2[(5x2−3y2)+(x2−2xy)]
=[10x2−6y2)+(2x2−4xy)]
=12x2−6y2−4xy
So, the perimeter of the rectangle is12x2−6y2−4xy.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution