Question
There is a uniform electric field of strength 103 V/m along y-axis. A body of mass 1g and charge 10−6C is projected into the field from origin along the positive x-axis with a velocity 10m/s. Its speed in m/s after 10s is (Neglect gravitation)
Answer: Option C
:
C
Body moves along the parabolic path.
For vertical motion : By using v=u+at
⇒vy=0+QEm.t=10−6×10310−3×10=10m/sec
For horizontal motion - it;s horizontal velocity remains the same i.e after the same i.e after 10 sec, horizontal
velocity of body vx=10m/sec.
Velocity aftey 10 sec v=√V2x+V2y=10√2m/sec
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:
C
Body moves along the parabolic path.
For vertical motion : By using v=u+at
⇒vy=0+QEm.t=10−6×10310−3×10=10m/sec
For horizontal motion - it;s horizontal velocity remains the same i.e after the same i.e after 10 sec, horizontal
velocity of body vx=10m/sec.
Velocity aftey 10 sec v=√V2x+V2y=10√2m/sec
Was this answer helpful ?
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