Question
There are 13 couples, 5 single males and 7 single females in party. Every male shakes hand with every female once. But none shakes hand with his wife. How many handshakes in total took place in the party?
Answer: Option B
:
B
There are 13 couples: 13 males & 13 females In addition to it, there are 5 single males and 7 single females Now, 5 single males can shake hands with 20 females, therefore 5*20 = 100 ways Also, each of 13 males (from the couples) can shake hands with 12 females (except his wife) + 7 single females. So 13 * 19 = 247 ways. Therefore, in total 347 ways
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:
B
There are 13 couples: 13 males & 13 females In addition to it, there are 5 single males and 7 single females Now, 5 single males can shake hands with 20 females, therefore 5*20 = 100 ways Also, each of 13 males (from the couples) can shake hands with 12 females (except his wife) + 7 single females. So 13 * 19 = 247 ways. Therefore, in total 347 ways
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