Question
The voltage across a bulb is decreased by 2%. Assuming that the resistance of the filament remains unchanged the power of the bulb will
Answer: Option C
:
C
Power P=v2R
Therefore △P=2V△VR
Hence △PP=2△VV
Now △VV=−2%
Therefore △PP=−2×2=−4% i.e. the power decreases by 4%
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:
C
Power P=v2R
Therefore △P=2V△VR
Hence △PP=2△VV
Now △VV=−2%
Therefore △PP=−2×2=−4% i.e. the power decreases by 4%
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