Question
Figure shows a network of resistances connected to a 2 V battery. If the internal resistance of the battery is negligible current I in the circuit is
Â
Â
Answer: Option B
:
B
Because PQ=RS the circuit is balanced Wheatstone's bride.Therefore potential at B =potential at D. Hence no current flows through the 5 ohm resistor. It is therefore not effectiveThe equivalent resistance between A and C is the resistance of a parallel combination of P + R = 2 + 4 = 6ohm and Q + S = 4 + 8 = 12ohm which is given by
1R+16+112
R = 4ohm
Therefore current l is
l=24=0.5 A
Was this answer helpful ?
:
B
Because PQ=RS the circuit is balanced Wheatstone's bride.Therefore potential at B =potential at D. Hence no current flows through the 5 ohm resistor. It is therefore not effectiveThe equivalent resistance between A and C is the resistance of a parallel combination of P + R = 2 + 4 = 6ohm and Q + S = 4 + 8 = 12ohm which is given by
1R+16+112
R = 4ohm
Therefore current l is
l=24=0.5 A
Was this answer helpful ?
Submit Solution