Question
The velocity - time graph of a particle moving in a straight line is shown in figure. The mass of the particle is 2kg.Work done by all the forces acting on the particle in time interval between t = 0 to t = 10 s is
Answer: Option A
:
A
From work - energy theorem,
W = △KE=Kf−Ki=12m(vf2−vi2)
=12×2[(−20)2−(10)2]=300J
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:
A
From work - energy theorem,
W = △KE=Kf−Ki=12m(vf2−vi2)
=12×2[(−20)2−(10)2]=300J
Was this answer helpful ?
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