The temperature field of a slab is given by T = 400 - 50z exp(-t - x2 - y2). The temperature gradient in y-direction is Options: A . &nbsp100yz exp(-t - x2 - y2) B . &nbsp-100yz exp(-t - x2 - y2) C . &nbsp100xz exp(-t - x2 - y2) D . &nbsp-100xz exp(-t - x2 - y2)

The temperature field of a slab is given by T = 400 - 50z exp(-t - x2

Question

The temperature field of a slab is given by T = 400 - 50z exp(-t - x2 - y2). The temperature gradient in y-direction is

Options:

A . 100yz exp(-t - x2 - y2)

B . -100yz exp(-t - x2 - y2)

C . 100xz exp(-t - x2 - y2)

D . -100xz exp(-t - x2 - y2)

Answer: Option A

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