Question
The simplification value of $$\left( {\sqrt 3 + 1} \right)$$ $$\left( {10 + \sqrt {12} } \right)$$ $$\left( {\sqrt {12} - 2} \right)$$ $$\left( {5 - \sqrt 3 } \right)$$ is = ?
Answer: Option C
$$\eqalign{
& \left( {\sqrt 3 + 1} \right)\left( {10 + \sqrt {12} } \right)\left( {\sqrt {12} - 2} \right)\left( {5 - \sqrt 3 } \right) \cr
& \Rightarrow \left( {\sqrt 3 + 1} \right)\left( {10 + 2\sqrt 3 } \right)\left( {2\sqrt 3 - 2} \right)\left( {5 - \sqrt 3 } \right) \cr} $$
$$ \Rightarrow \left( {\sqrt 3 + 1} \right) \times $$ $$2\left( {5 + \sqrt 3 } \right) \times $$ $$2\left( {\sqrt 3 - 1} \right)$$ $$\left( {5 - \sqrt 3 } \right)$$
$$\eqalign{
& \Rightarrow 4\left( {\sqrt 3 + 1} \right)\left( {\sqrt 3 - 1} \right)\left( {5 + \sqrt 3 } \right)\left( {5 - \sqrt 3 } \right) \cr
& \Rightarrow 4\left[ {{{\left( {\sqrt 3 } \right)}^2} - {1^2}} \right]\left[ {{{\left( 5 \right)}^2} - {{\left( {\sqrt 3 } \right)}^2}} \right] \cr
& \Rightarrow 4 \times 2 \times 22 \cr
& \Rightarrow 176 \cr} $$
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$$\eqalign{
& \left( {\sqrt 3 + 1} \right)\left( {10 + \sqrt {12} } \right)\left( {\sqrt {12} - 2} \right)\left( {5 - \sqrt 3 } \right) \cr
& \Rightarrow \left( {\sqrt 3 + 1} \right)\left( {10 + 2\sqrt 3 } \right)\left( {2\sqrt 3 - 2} \right)\left( {5 - \sqrt 3 } \right) \cr} $$
$$ \Rightarrow \left( {\sqrt 3 + 1} \right) \times $$ $$2\left( {5 + \sqrt 3 } \right) \times $$ $$2\left( {\sqrt 3 - 1} \right)$$ $$\left( {5 - \sqrt 3 } \right)$$
$$\eqalign{
& \Rightarrow 4\left( {\sqrt 3 + 1} \right)\left( {\sqrt 3 - 1} \right)\left( {5 + \sqrt 3 } \right)\left( {5 - \sqrt 3 } \right) \cr
& \Rightarrow 4\left[ {{{\left( {\sqrt 3 } \right)}^2} - {1^2}} \right]\left[ {{{\left( 5 \right)}^2} - {{\left( {\sqrt 3 } \right)}^2}} \right] \cr
& \Rightarrow 4 \times 2 \times 22 \cr
& \Rightarrow 176 \cr} $$
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