The resultant of → P and → Q is perpendicular to → P . What is the angle between → P and → Q . Options: A . &nbspcos−1(PQ) B . &nbspcos−1(−PQ) C . &nbspsin−1(PQ) D . &nbspsin−1(−PQ)

Answer: Option B : B ⇒ tan 90 ∘ = Q s i n θ P + Q c o s θ ⇒ P + Q cos θ = 0 cos θ = − P Q ∴ θ = c o s − 1 ( − P Q )

The resultant of →P and →Q is perpendicular to →P. What is the angle be

Question

The resultant of

\to P

and

\to Q

is perpendicular to

\to P

. What is the angle between

\to P

and

\to Q

Options:

A . cos−1(PQ)

B . cos−1(−PQ)

C . sin−1(PQ)

D . sin−1(−PQ)

Answer: Option B
:
B

The Resultant Of →P And →Q Is Perpendicular To →P. ...

\Rightarrow

tan

90^{\circ}

\frac{Q s i n θ}{P + Q c o s θ}

\Rightarrow

P + Q cos

θ

= 0
cos

θ

\frac{- P}{Q}

∴

θ

{c o s}^{- 1}

(

\frac{- P}{Q}

)

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