Question
The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘a’ is 3:2. The value of ‘a’ is (g – Acceleration due to gravity on the earth)
Answer: Option B
:
B
weightofamaninstationaryliftweightofamanindownwardmovinglift=mgm(g−a)=32gg−a=32⇒2g=3g−3aora=g3
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B
weightofamaninstationaryliftweightofamanindownwardmovinglift=mgm(g−a)=32gg−a=32⇒2g=3g−3aora=g3
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