Question
A 60 kg man stands on a spring scale in the lift. At some instant he finds, scale reading has changed from 60 kg to 50 kg for a while and then comes back to the original mark. What should we conclude
Answer: Option C
:
C
For retarding motion of a lift R = m(g + a) for downward motion
R = m(g – a) for upward motion
Since the weight of the body decrease for a while and then comes back to original value it means the lift was moving upward and stops suddenly.
Note: Generally we use R = m(g + a) for downward motion
R = m(g – a) for upward motion
Here a = acceleration, but for the given problem a = retardation
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:
C
For retarding motion of a lift R = m(g + a) for downward motion
R = m(g – a) for upward motion
Since the weight of the body decrease for a while and then comes back to original value it means the lift was moving upward and stops suddenly.
Note: Generally we use R = m(g + a) for downward motion
R = m(g – a) for upward motion
Here a = acceleration, but for the given problem a = retardation
Was this answer helpful ?
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