Question
The number of integral terms in the expansion of (512+716)642 is
Answer: Option B
:
B
Tr+1 =642Cr(512)642−r.(716)r
Obviously, r should be a multiple of 6.
Total number of terms= 6426 = 107,
but first term forr = 0 is also an integer. Hence total terms are 107 + 1 = 108.
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:
B
Tr+1 =642Cr(512)642−r.(716)r
Obviously, r should be a multiple of 6.
Total number of terms= 6426 = 107,
but first term forr = 0 is also an integer. Hence total terms are 107 + 1 = 108.
Was this answer helpful ?
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