Question
The marked price of watch was Rs.820. A man bought the watch for Rs.570.72 after getting two successive discounts, of which the first was 20%. The second discount was
Answer: Option B
Answer: (b)Total discount=Rs.(820 - 570.72) = Rs.249.28First discount = $820 × 20/100$ = Rs.164Second discount= Rs.(249.28 - 164) = Rs.85.28Price of the article after first discount= Rs.(820 - 164) = Rs.656If the second discount be x% , thenx% of 656 = 85.28$x = {85.28 × 100}/656 = 13%$Using Rule 3,Here, M.P. = Rs.820, S.P. = 570.72, $D_1 = 20%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$$570.72 = 820 ({100 - 20}/100)({100 - D_2}/100)$$5707200/{820 × 80} = 100 - D_2$$100 - D_2 = 87 ⇒ D_2$ = 13%
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Answer: (b)Total discount=Rs.(820 - 570.72) = Rs.249.28First discount = $820 × 20/100$ = Rs.164Second discount= Rs.(249.28 - 164) = Rs.85.28Price of the article after first discount= Rs.(820 - 164) = Rs.656If the second discount be x% , thenx% of 656 = 85.28$x = {85.28 × 100}/656 = 13%$Using Rule 3,Here, M.P. = Rs.820, S.P. = 570.72, $D_1 = 20%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$$570.72 = 820 ({100 - 20}/100)({100 - D_2}/100)$$5707200/{820 × 80} = 100 - D_2$$100 - D_2 = 87 ⇒ D_2$ = 13%
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