The initial velocity of a particle is 10 m/sec and its retardation is

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The initial velocity of a particle is 10 m/sec and its retardation is 2 m/

s e c^{2}

. The distance moved by the particle in

5^{t h}

second of its motion is

Options:

A . 1 m

B . 19 m

C . 50 m

D . 75 m

Answer: Option A
:
A
Using the formula for the distance travelled in the

n^{t h}

second

S_{n} = u - \frac{a}{2} (2 n - 1) = 10 - \frac{2}{2} (2 \times 5 - 1) = 1

meter

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