Question
A body is moving from rest under constant acceleration and let S1 be the displacement in the first (p−1) seconds and S2 be the displacement in the first p seconds. The displacement in (p2−p+1)th second will be
Answer: Option A
:
A
From S=ut+12at2
S1=12a(p−1)2 andS2=12ap2 [As u = 0]
We have
S1+S2=a2[2p2−2p+1]
Using the expression for distance traveled in nthsecond
Sn=u+a2(2n−1)
S(p2−p+1)th=a2[2(p2−p+1)−1]=a2[2p2−2p+1]
It is clear that S(p2−p+1)th=S1+S2
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:
A
From S=ut+12at2
S1=12a(p−1)2 andS2=12ap2 [As u = 0]
We have
S1+S2=a2[2p2−2p+1]
Using the expression for distance traveled in nthsecond
Sn=u+a2(2n−1)
S(p2−p+1)th=a2[2(p2−p+1)−1]=a2[2p2−2p+1]
It is clear that S(p2−p+1)th=S1+S2
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