Question
A motor car moving with a uniform speed of 20 ms−1 comes to rest on the application of brakes after travelling a distance of 10 m. Its acceleration is
Answer: Option B
:
B
Using, v2=u2+2aS
⇒o=u2+2aS
⇒a=−u22S
a=−(20)22×10
a=−20ms−2
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:
B
Using, v2=u2+2aS
⇒o=u2+2aS
⇒a=−u22S
a=−(20)22×10
a=−20ms−2
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