Question
The dimensions of universal gravitational constant are
Answer: Option B
:
B
F=Gm1m2d2⇒ G =Fd2m1m2
∴[G]=[MLT−2][L2][M2]=[M−1L3T−2]
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B
F=Gm1m2d2⇒ G =Fd2m1m2
∴[G]=[MLT−2][L2][M2]=[M−1L3T−2]
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