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Question
The difference in voids ratio ∆e of initial and increased pressure is given by __________
Options:
A .  \(∆e=log_{10}\frac{σ’_0+∆σ’}{σ’_0}\)
B .  \(∆e=C_c \frac{σ’_0+∆σ’}{σ’_0}\)
C .  \(∆e=C_c log_{10} \frac{σ’_0+∆σ’}{σ’_0}\)
D .  \(∆e=C_c log_{10} \frac{σ’_0}{σ’_0} \)
Answer: Option C
Answer: (c).\(∆e=C_c log_{10} \frac{σ’_0+∆σ’}{σ’_0}\)

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