The diagonal of a rectangle divides it into 2 congruent triangles.

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The diagonal of a rectangle divides it into 2 congruent triangles.

Options:

A . True

B . False

C . CA

D . All are same in length

Answer: Option A
:
A

In $△$ ABC and $△$ CDA, we have:

AB = CD (Opposite sides of a parallelogram)

BC = AD (Opposite sides of a parallelogram)

AC = AC (Common)

By SSS congruence condition, $△$ ABC $≅$ $△$ CDA. So, the diagonal of the parallelogram divides it into two congruent triangles.

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