In the given figure, Δ A B C and Δ O B C are both isosceles. It can be concluded that: Options: A . &nbsp Δ A O B ≅ Δ A O C B . &nbsp AB = AO C . &nbsp ∠ A B O = ∠ A C O D . &nbsp Δ A O B is not congruent to Δ A O C

Answer: Option A : A and C In Δ A O B and Δ A O C , A B = A C (Sides of isosceles Δ A B C ) . O B = O C (Sides of isosceles Δ O B C ) . A O i s c o m m o n ∴ Δ A O B ≅ Δ A O C (by SSS congruence) And ∠ A B O = ∠ A C O ( By CPCT)

In the given figure, ΔABC and ΔOBC are both isosceles.It can be concluded

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