Question
The degree of the differential equation satisfying the relation √1+x2+√1+y2=λ(x√1+y2−y√1+x2) is
Answer: Option A
:
A
On Putting x=tanA,y=tanB we get
secA+secB=λ(tanAsecB−tanBsecA)cosA+cosB=λ(sinA−sinB)tan(A−B2)=1λtan−1x−tan−1y=2tan−11λ
On differentiating 11+x2−11+y2dydx=0
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:
A
On Putting x=tanA,y=tanB we get
secA+secB=λ(tanAsecB−tanBsecA)cosA+cosB=λ(sinA−sinB)tan(A−B2)=1λtan−1x−tan−1y=2tan−11λ
On differentiating 11+x2−11+y2dydx=0
Was this answer helpful ?
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