Question
Solution of the differential equation : dydx=3x2y4+2xyx2−2x3y3 is
Answer: Option B
:
B
x2dy−2x3y3dy=3x2y4dx+2xydx⇒x2dy−2xydx=3x2y4dx+2x3y3dy⇒2xydx−x2dyy2+3x2y2dx+2x3ydy=0⇒d(x2y)+d(x3y2)=0⇒x2y+x3y2=C
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B
x2dy−2x3y3dy=3x2y4dx+2xydx⇒x2dy−2xydx=3x2y4dx+2x3y3dy⇒2xydx−x2dyy2+3x2y2dx+2x3ydy=0⇒d(x2y)+d(x3y2)=0⇒x2y+x3y2=C
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