Answer: Option C
To find the solution, we need to understand the concept of the 'odd days'.
Odd Days:Odd days are the extra days that remain after we divide a number of days by seven. For example, when we divide 365 by 7, we get 52 weeks and one day left over. So, the number of odd days is one.
To find the day on a particular date, we need to know the number of days between that date and a known reference date. The reference date is usually taken as 1st January of the same year.
Now, let's use this concept to solve the given question.
We know that the day on 5th March is the same as the day on some other date of the same year. We need to find that date.
First, we need to find the number of days between 1st January and 5th March.
Number of days from 1st January to 5th March = 31 + 28 + 5 = 64 days
Now, we know that there are 2 odd days in 64 days (as 64 divided by 7 leaves a remainder of 2).
So, the day on 5th March will be 2 days ahead of the day on 1st January.
Now, we need to find the date on which the day is also 2 days ahead of 1st January.
We can start from 1st January and keep adding days until we get a date that is 2 days ahead of it.
We can do this by adding the number of days in each month until we get a total of 62 days (since 64 days will take us to 2 days ahead of 1st January).
January - 31 daysFebruary - 28 daysMarch (till 5th) - 5 days
Total = 31 + 28 + 5 = 64 days (2 odd days)
So, the day on 5th March will be the same as the day on 5th November of the same year. Therefore, the correct answer is option C.If you think the solution is wrong then please provide your own solution below in the comments section .