Question
The coefficient of variation of two series are 58% and 69%. If their standard deviations are 21.2 and 15.6, then their A.Ms are
Answer: Option A
:
A
We know thatC.V =σ×100¯xor¯x=σc.v×100∴Mean of first series =21.2×10058=36.6Mean of second series =15.6×10069=22.6
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:
A
We know thatC.V =σ×100¯xor¯x=σc.v×100∴Mean of first series =21.2×10058=36.6Mean of second series =15.6×10069=22.6
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