Question
The circumference of first orbit of hydrogen atom is ‘s’. Then the Broglie wavelength of electron in that orbit is
Answer: Option C
:
C
2πrn=nλ
n=1
2πr1=λ
λ=2πr1=S
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:
C
2πrn=nλ
n=1
2πr1=λ
λ=2πr1=S
Was this answer helpful ?
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