Energy levels A,B,C of an atom are shown belowIf EA<EB<EC, the wavelength

Question

Energy levels A,B,C of an atom are shown below

E_{A} < E_{B} < E_{C}

, the wavelength emitted due to transistion from C to A is

λ_{3}

then correct statements of the following is

Options:

A . λ3=λ1+λ2

B . λ3=λ1×λ2λ2+λ1

C . λ1+λ2+λ3=0

D . λ23=λ21+λ22

Answer: Option B
:
B

E_{C A} = E_{C B} + E_{B A}

\frac{h c}{λ_{3}} = \frac{h c}{λ_{1}} + \frac{h c}{λ_{2}}

λ_{3} = \frac{λ_{1} \times λ_{2}}{λ_{2} + λ_{1}}

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