The binding energy per nucleon of deuteron (21H) and helium nucleus (42He) is 1.

Question

The binding energy per nucleon of deuteron

(_{1}^{2} H)

and helium nucleus

(_{2}^{4} H e)

is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Options:

A . 13.9 MeV

B . 26.9 MeV

C . 23.6 MeV

D . 19.2 MeV

Answer: Option C
:
C

_{1} H^{2} +_{1} H^{2} \to_{2} H e^{4} + Q

Total binding energy of helium nucleus =

4 \times 7 = 28 M e V

Total binding energy of each deutron =

2 \times 1.1 = 2.2 M e V

Hence energy released =

28 - 2 \times 2.2 = 23.6 M e V

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