Question
A radioactive substance has a half life of 60 minutes. After 3 hours, the percentage of atom that have decayed would be
Answer: Option B
:
B
N=N0(12)tT1/2. Hence fraction of atoms decayed
=1−NN0=1−(12)tT1/2=1−(12)3×6060=78
In percentage it is 78×100=87.5%
Was this answer helpful ?
:
B
N=N0(12)tT1/2. Hence fraction of atoms decayed
=1−NN0=1−(12)tT1/2=1−(12)3×6060=78
In percentage it is 78×100=87.5%
Was this answer helpful ?
Submit Solution