Question
A atomic power reactor furnace can deliver 300 MW. The energy released due to fission of each of uranium atom U238 is 170 MeV. The number of uranium atoms fission per hour will be
Answer: Option C
:
C
By using P=Wt=n×Et where n = Number of uranium atom fission and E = Energy released due to each fission so 300×106=n×170×106×1.6×10−193600⇒n=40×1021
Was this answer helpful ?
:
C
By using P=Wt=n×Et where n = Number of uranium atom fission and E = Energy released due to each fission so 300×106=n×170×106×1.6×10−193600⇒n=40×1021
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution