Question
The value of p for which the points (–1, 3), (2, p), (5, –1) are collinear is
Answer: Option B
:
B
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B
The given points A(-1, 3), B(2, p), C(5, -1) are collinear.
⇒ Area ΔABC formed by these points should be zero.
⇒ The area of ΔABC = 0
⇒ 12( x1( y2- y3) + x2( y3- y1) + x3( y1 - y2)) = 0
⇒ -1(p + 1) + 2 (-1 - 3) + 5(3 -p) = 0
⇒ -p - 1 - 8 + 15 - 5p = 0
⇒ -6p +15 - 9 = 0 ⇒ -6p = -6 ⇒ p = 1
Hence the value of p is 1.
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