Question
The area of a square is 4096 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square.
Answer: Option E
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Let the length and the breadth of the rectangle be l cm and b cm respectively. Let the side of the square be a cm. a2 = 4096 = 212 a = (212)1/2 = 26 = 64 L = 2a and b = a - 24 b : l = a - 24 : 2a = 40 : 128 = 5 : 16
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