Question
The angle between the pair of straight lines x2+4y2−7xy=0, is
Answer: Option C
:
C
tanθ=2√h2−aba+b
θ=tan−12√494−45=tan−1√335.
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:
C
tanθ=2√h2−aba+b
θ=tan−12√494−45=tan−1√335.
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