Question
Let PS be the median of the triangle with vertices P(2, 2), Q(6, -1) and R(7, 3). The equation of the line passing through (1, -1) and parallel to PS is
Answer: Option D
:
D
S = midpoint of QR = (6+72,−1+32)=(132,1)∴slope ofPS=2−12−132=−29∴The required equation isy+1=−29(x−1)i.e.,2x+9y+7=0
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D
S = midpoint of QR = (6+72,−1+32)=(132,1)∴slope ofPS=2−12−132=−29∴The required equation isy+1=−29(x−1)i.e.,2x+9y+7=0
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