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Let PS be the median of the triangle with vertices P(2, 2), Q(6, -1) and R(7, 3). The equation of the line passing through (1, -1) and parallel to PS is
Options:
A .  2x – 9y – 7 = 0
B .  2x – 9y – 11 = 0
C .  2x + 9y – 7 = 0
D .  2x – 9y + 7 = 0
Answer: Option D
:
D
S = midpoint of QR = (6+72,1+32)=(132,1)slope ofPS=212132=29The required equation isy+1=29(x1)i.e.,2x+9y+7=0

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