The angle between the pair of straight lines x2+4y2−7xy=0, is

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Question

The angle between the pair of straight lines

x^{2} + 4 y^{2} - 7 x y = 0,

is

Options:

A . tan−113

B . tan−13

C . tan−1√335

D . tan−15√33

Answer: Option C
:
C

tan θ = \frac{2 \sqrt{h^{2} - a b}}{a + b}

θ = t a n^{- 1} \frac{2 \sqrt{\frac{49}{4} - 4}}{5} = t a n^{- 1} \frac{\sqrt{33}}{5}

.

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