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Question

The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:

Options:
A .  0º
B .  10º
C .  5º
D .  20º
Answer: Option B

Angle traced by hour hand in  \(\frac{13}{3}hrs = \left(\frac{360}{12}\times\frac{13}{3}\right)^{0}=130^{0}\)


Angle traced by min. hand in 20 min \(\left(\frac{360}{60}\times20\right)^{0}=120^{0}\)


So, Required angle = (130 - 120)º = 10º.


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