Question
At what angle the hands of a clock are inclined at 15 minutes past 5?
Answer: Option C
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Angle traced by hour hand in \(\frac{21}{4}hrs = \left(\frac{360}{12}\times\frac{21}{4}\right)^{0}=157\frac{1}{2}^{0} \)
Angle traced by min. hand in 15 min. = \(\left(\frac{360}{60}\times15\right)^{0}=90^{0} \)
So, Required angle = \(\left(157\frac{1}{2}\right)^{0}-90^{0} =67\frac{1}{2}^{0}\)
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