Question
The ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages?
Answer: Option A
- Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
:. 3 (x - 6) = (x + 16 - 6) => 3x -18 = x + 10
Was this answer helpful ?
- Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
:. 3 (x - 6) = (x + 16 - 6) => 3x -18 = x + 10
2x = 28 => x = 14
Hence, their present ages are 14 years and 30 years.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution