-  Let the ages of Abhay and his father 10 yearsago be x and 5x years respectively. Then,
  
    Abhay's age after 6 years = (x + 10) + 6 = (x + 16) years.
    Father's age after 6 years = (5x + 10) + 6 = (5x + 16) years.
                  
(x + 16) = 3(5x + 16)
7 (x + 16) = 3 (5x + 16)
7x + 112 = 15x + 48
8x = 64 
x = 8.
Hence, Abhay's father's present age = (5x + 10) = 50 years

Let the present age of Abhay be A and his father be F.

Given, after six years, Abhay's age will be 3/7 of his father's age.

So, we can form the equation:

A + 6 = (3/7)(F + 6)

Also, ten years ago, the ratio of their ages was 1:5.

So, we can form another equation:

(A-10)/(F-10) = 1/5

We need to find Abhay's father's age at present, i.e., F.

Let's solve these equations one by one:

Equation 1:

A + 6 = (3/7)(F + 6)

7A + 42 = 3F + 18

7A = 3F - 24

Equation 2:

(A-10)/(F-10) = 1/5

5(A-10) = F-10

5A - 50 = F - 10

5A = F + 40

Now, we have two equations with two variables (A and F). We can solve for F by eliminating A.

Multiplying equation 1 by 5 and equation 2 by 7, we get:

35A = 15F - 120 ...(3)

35A = 7F + 280 ...(4)

Subtracting equation 3 from equation 4, we get:

22F = 400

F = 400/22

F = 50/11

Since we need to find F, we can round off 50/11 to the nearest integer.

50/11 is approximately equal to 4.54, which rounds off to 5.

Therefore, Abhay's father's age at present is approximately 50 years (Option C).

To verify, we can substitute F = 50 in any of the two equations we formed earlier and solve for A.

Using equation 1:

7A = 3F - 24

7A = 3(50) - 24

7A = 126

A = 18

Using equation 2:

5A = F + 40

5A = 50 + 40

5A = 90

A = 18

Both equations give the same value of A (Abhay's age at present), which confirms that our solution is correct.

Hence, the answer is option C.

If you think the solution is wrong then please provide your own solution below in the comments section .