One year ago, the ratio of Gaurav’s and Sachin’s age was 6: 7 respectively. Four years hence, this ratio would become 7: 8. How old is Sachin?
- Let Gaurav's and Sachin's ages one year ago be 6x and 7x years respectively. Then, Gaurav's age
4 years hence = (6x + 1) + 4 = (6x + 5) years.
Sachin's age 4 years hence = (7x + 1) + 4 = (7x + 5) years.
6x+5 = 7
8(6x+5) = 7 (7x + 5)
48x + 40 = 49x + 35
x = 5.
Hence, Sachin's present age = (7x + 1) = 36 years.
Let's assume that Gaurav's age one year ago was 6x and Sachin's age was 7x. Therefore, their current ages would be (6x + 1) and (7x + 1) respectively.
According to the problem statement, after four years, the ratio of their ages would be 7:8. Therefore, we can form an equation as follows:
(6x + 5) + 4 : (7x + 5) + 4 = 7 : 8
Simplifying the equation, we get:
(6x + 9) : (7x + 9) = 7 : 8
We can cross-multiply to get:
8(6x + 9) = 7(7x + 9)
Solving this equation, we get:
48x + 72 = 49x + 63
x = 9
Therefore, Sachin's age one year ago was 7x = 63, and his current age is 63+1= 64 years.
Hence, the correct answer is option B, 36.
To summarize the solution, we can use the following bullet points:
- Let Gaurav's age one year ago be 6x and Sachin's age one year ago be 7x.
- Their current ages are (6x + 1) and (7x + 1) respectively.
- After four years, the ratio of their ages becomes 7:8.
- Using the ratio, we form an equation and simplify it to get 8(6x + 9) = 7(7x + 9).
- Solving this equation gives x = 9.
- Therefore, Sachin's age one year ago was 63 and his current age is 64.
- Hence, the correct answer is option B, 36.
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