Question
sin−1|cosx|−cos−1|sinx|=a has at least one solution if a ∈
Answer: Option A
:
A
sin−1|cosx|−cos−1|sinx|=π2−cos−1|cosx|−π2+sin−1|sinx|=a⇒sin−1|sinx|−cos−1|cosx|=a⇒a=0∀x
Was this answer helpful ?
:
A
sin−1|cosx|−cos−1|sinx|=π2−cos−1|cosx|−π2+sin−1|sinx|=a⇒sin−1|sinx|−cos−1|cosx|=a⇒a=0∀x
Was this answer helpful ?
More Questions on This Topic :
Question 2. Tan[2tan−1(15)−π4]=....
Question 4. 3cos−1x−πx−π2=0 has : ....
Question 5. The value of cos−1(cos12)−sin−1(sin14) is....
Question 6. 4tan−115−tan−11239 is equal to....
Question 7. If cos−1x+cos−1y+cos−1z=3π, then xy+yz+zx=
....
Question 8. Sin(12cos−145)=....
Question 9. Cos−1x=tan−1√1−x2x, then:
....
Submit Solution